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23. write each logarithm in terms of log3 and log5: a) log 45, b) log Log 3 a Given log3=0.4772, log7=0.8451, log5=0.6990, log2=0.3010, how do you
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Given Log3=0.4772, log7=0.8451, log5=0.6990, log2=0.3010, how do you
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Answered: 2log5(x-3) - log5(8) = log5(2) | bartleby
How do you evaluate log_2 0.5+log_4 4-log_5 25 without a calculator
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